Sequence and Series - Sigma Notation By Substitution

Sequence and Series - Sigma Notation By Substitution

7 marks
  1. Find \(\sum_{r=0}^{k}\left(2r + 5 - 3^{1-r}\right)\) in terms of \(k\), simplifying your answer.[4]
  2. Using the result in part (i), find \(\sum_{r=0}^{k}\left(2r + 9 - 3^{-r-1}\right)\) in terms of \(k\).[3]

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Answer:(i) \((k+1)(k+5)-\dfrac92\left(1-\dfrac1{3^{k+1}}\right)\) (ii) \((k+3)(k+7)+\dfrac9{2\cdot3^{k+3}}-\dfrac{25}2\)

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