Given that \(\sum\limits_{r=1}^{n}{r}=\frac{n}{2}(n+1)\), \(\sum\limits_{r=1}^{n}{{{r}^{2}}}=\frac{1}{6}n\left( n+1 \right)\left( 2n+1 \right)\) and \(\sum\limits_{r=1}^{n}{{{r}^{3}}}=\frac{1}{4}{{n}^{2}}{{\left( n+1 \right)}^{2}}={{\left[ \frac{1}{2}n\left( n+1 \right) \right]}^{2}}\).
Find, in terms of \(n\),
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