A Summation Identity
A Summation Identity
IB Year 5 | Grade 11
Prove by mathematical induction that \(\displaystyle\sum_{r=1}^{n} r(r+1)=\dfrac{n(n+1)(n+2)}3\) for every \(n\in\mathbb Z^+\).
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Answer:\(\displaystyle\sum_{r=1}^{n} r(r+1)=\dfrac{n(n+1)(n+2)}3\)
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