Method of Difference Q1
Method of Difference Q1
By expressing \(\frac{1}{(4r-1)(4r+3)}\) in partial fractions, evaluate \(\sum\limits_{r=1}^{n}{\frac{1}{(4r-1)(4r+3)}}\).
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Answer:\(\frac{1}{4}\left( \frac{1}{3}-\frac{1}{4n+3} \right)\)
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