Recovering a logarithmic graph equation

Recovering a logarithmic graph equation

6 marks
TGM Original
A curve has equation y=kln(ax+b), where k,a,b are integers and ka 0. Its vertical asymptote is x=1, it crosses the x-axis at (2,0), and it passes through (1+ e2,4). Find k,a,b, then sketch the curve.

Solution:

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Answer:\(k=2,a=1,b=-1\); \(y=2\ln(x-1)\), \(x>1\).

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