Recover the equation of a curve
Recover the equation of a curve
IB Year 6 | Grade 12
The gradient of a curve at any point \(x,y\) on it is \(\tan (2x)\) and this curve passes through the point \(\left( \frac{\pi}{6}, 0 \right)\). Find the equation of the curve.
Solution:
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Answer:\(y=-\frac12\ln(2\cos2x)\), \(-\frac\pi4<x<\frac\pi4\).
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