The roots of the equation $x^2-6x+4=0$ are $\alpha$ and $\beta$. Without solving the equation,

Question

The roots of the equation $x^2-6x+4=0$ are $\alpha$ and $\beta$. Without solving the equation, find the value of each of the following. $\dfrac{1}{\alpha}+\dfrac{1}{\beta}$ $\alpha^2+\beta^2$

Accepted Answer

(a) $\frac{3}{2}$ (b) $28$

Reciprocal sum and sum of squares

Reciprocal sum and sum of squares

Solution:

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