The curve $y=\dfrac{12}{x^2}$ meets the line $y=3$ at $A$, where the $x$-coordinate of $A$

Question

The curve $y=\dfrac{12}{x^2}$ meets the line $y=3$ at $A$, where the $x$-coordinate of $A$ is $p>0$. Find the value of $p$.[2] Hence find the area bounded by the curve, the line and the line $x=1$.[5]

Accepted Answer

(i) $p=2$ (ii) $3\text{ units}^2$

Reciprocal-square curve above a horizontal line

Reciprocal-square curve above a horizontal line

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