$y=\mathrm{f}\left( x \right)$ $y=\frac{1}{\mathrm{f}\left( x \right)}$ \(y=\mathrm{f}'\left( x

Question

$y=\mathrm{f}\left( x \right)$ $y=\frac{1}{\mathrm{f}\left( x \right)}$ $y=\mathrm{f}'\left( x \right)$

Accepted Answer

For $y=\dfrac1{f(x)}$: vertical asymptote $x=-1$, horizontal asymptote $y=0$, open limiting point $(-2,0)$, minimum $B'\left(-3,-\dfrac14\right)$. For $y=f'(x)$: vertical asymptote $x=-2$, horizontal asymptote $y=1$, zeros $(-3,0)$ and $(-1,0)$; positive for $x-1$, negative for $-3<x<-2$ and $-2<x<-1$.

Prelims Revision Set: Reciprocal and Gradient Graphs Q6

Prelims Revision Set: Reciprocal and Gradient Graphs Q6

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