$y=\mathrm{f}\left( x \right)$ $y=\frac{1}{\mathrm{f}\left( x \right)}$ \(y=\mathrm{f}'\left( x

Question

$y=\mathrm{f}\left( x \right)$ $y=\frac{1}{\mathrm{f}\left( x \right)}$ $y=\mathrm{f}'\left( x \right)$

Accepted Answer

$\displaystyle y=\frac{1}{\mathrm{f}(x)}$: vertical asymptote $x=0$, horizontal asymptote $y=0$, removable hole at $(2,0)$, maximum at $\left(4,\frac{1}{8}\right)$ $y=\mathrm{f}'(x)$: zeros at $x=0,4$, vertical asymptote $x=2$, horizontal asymptote $y=1$

Transformations of Graphs - Reciprocal Graph, \(y=\frac{1}{f(x)}\)

Transformations of Graphs - Reciprocal Graph, \(y=\frac{1}{f(x)}\)

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