Rearranging a Radical Equation to Make \(𝑥\) the Subject

Rearranging a Radical Equation to Make \(𝑥\) the Subject

Secondary 2

Make \(x\) the subject of the given formula \(\sqrt{\frac{2}{y}}=\sqrt{\frac{5x+3}{x-5}}\).
Find \(x\), when \(y=0.02\).

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Answer:(a) \(x=\frac{3y+10}{2-5y}\), where \(y>0\) and \(y\ne\frac25\) (b) \(x=\frac{503}{95}=5\frac{28}{95}\)

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