Rearranging a Fractional Formula to Make \(𝑎\) the Subject
Rearranging a Fractional Formula to Make \(𝑎\) the Subject
Secondary 2
Make \(a\) the subject of the formula \(\frac{1}{3b}=\frac{2}{3a}+\frac{1}{5c}\).
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Answer:\( a = \dfrac{10bc}{5c - 3b} \)
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