Real solutions and squares

Real solutions and squares

Secondary 3
3 marks
TGM Original Questions

Consider the equation \(x^2+4x+7=0\).

  1. Express \(x^2+4x+7\) in the form \((x+a)^2+b\).[2]
  2. Use your answer to explain why the equation has no real solution.[1]

Solution:

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Answer:(a) \((x+2)^2+3\) (b) No real solution, since \((x+2)^2+3\ge3\).

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