Quotients of functions
Quotients of functions
4 marks
TGM Original
Given y= sin(x)x + 2, x!= -2, find dydx.
Solution:
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Answer:\(\dfrac{\mathrm{d}y}{\mathrm{d}x}=\dfrac{\cos{\left(x \right)}}{x + 2} - \dfrac{\sin{\left(x \right)}}{\left(x + 2\right)^{2}}\)
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