Quotients of functions

Quotients of functions

4 marks
TGM Original
Given y= ln(x)x, x>0, find dydx. Hence find its value at x=1.

Solution:

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Answer:\(\dfrac{\mathrm{d}y}{\mathrm{d}x}=- \dfrac{\ln{\left(x \right)}}{x^{2}} + \dfrac{1}{x^{2}}\); at \(x=1\), \(1\).

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