<p>A curve is such that&nbsp;\(\frac{\mathrm{d}y}{\mathrm{d}x} = 4x - hx^2\) where&nbsp;\(h\) is a constant. Given that the curve has a turning point at \((4, 5)\),</p>
<ol class="abc-list"><li><div class="list-item-content"><span class="list-item-text">show that the value of \(h\) is \(1\).</span></div></li><li><div class="list-item-content"><span class="list-item-text">find the range of values of \(x\) for which \(y\) is an increasing function.</span></div></li></ol>

A curve is such that \(\frac{\mathrm{d}y}{\mathrm{d}x} = 4x - hx^2\) where \(h\) is a constant. Given that the curve has a turning point at \((4, 5)\),

find the range of values of \(x\) for which \(y\) is an increasing function.

Applications of Differentiation

Question 6101b610

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