<p>Evaluate the following</p>
<ol class="abc-list"><li><div class="list-item-paragraph">\(\displaystyle\int\nolimits_{0}^{\frac{\pi}{12}} 2 \sin 3x + \tan^2 2x \, \mathrm{d}x\)</div></li><li><div class="list-item-paragraph">\(\displaystyle\int\nolimits_{0}^{\frac{\pi}{3}} 5 \cos 2x + \tan^2 x \, \mathrm{d}x\)</div></li></ol>

\[\displaystyle\displaystyle \displaystyle\int\nolimits_{0}^{\frac{\pi}{4}} 2 \sin 3x + \tan^2 2x \, \mathrm{d}x\]

\(\displaystyle\displaystyle \displaystyle\int\nolimits_{0}^{\frac{\pi}{12}} 2 \sin 3x + \tan^2 2x \, \mathrm{d}x\)

\[\displaystyle\displaystyle \displaystyle\int\nolimits_{0}^{\frac{\pi}{3}} 5 \cos 2x + \tan^2 x \, \mathrm{d}x\]

\(\displaystyle\displaystyle \displaystyle\int\nolimits_{0}^{\frac{\pi}{3}} 5 \cos 2x + \tan^2 x \, \mathrm{d}x\)

Definite Integrals and Area under graph - Definite Integral

Question 52047c3c

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