<p>In the diagram, \(BFD\), \(AFC\) and \(BEC\) are straight lines. It is given that&nbsp;\(AF = FC\), \(BF = FD\) and \(BE = EC\). Prove that</p>
<div class="content-block"><figure class="question-figure aligncenter" style="text-align: center;"><img src="https://vocwkpgapvksartxhhor.supabase.co/storage/v1/object/public/question-images/pasted/1770110674989-lobiokjdn3.png" style="max-width: min(250px, 100%); height: auto; display: block;" class="aligncenter custom-width" /></figure></div>
<ol class="i-list"><li><div class="list-item-content"><span class="list-item-text">\(FE = \frac{1}{2} AB\), and</span></div></li><li><div class="list-item-content"><span class="list-item-text">\(AB = DC\).</span></div></li></ol>

In the diagram, \(BFD\), \(AFC\) and \(BEC\) are straight lines. It is given that \(AF = FC\), \(BF = FD\) and \(BE = EC\). Prove that

Proofs in Plane Geometry

Question 43b3a724