<p>At any point \((x, y)\) on a curve, \(\frac{\mathrm{d}^2y}{\mathrm{d}x^2} = \frac{18}{(x-2)^3}\). The gradient of the curve at \((5, 20)\) is \(2\).</p>
<p>Find the equation of the tangent to the curve when it cuts the \(y\)-axis.</p>

At any point \((x, y)\) on a curve, \(\frac{\mathrm{d}^2y}{\mathrm{d}x^2} = \frac{18}{(x-2)^3}\). The gradient of the curve at \((5, 20)\) is \(2\).

Find the equation of the tangent to the curve when it cuts the \(y\)-axis.

Definite Integrals and Area under graph - Finding Equation of Curve from Second Derivatives

Question 38ff20d3

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