<p>In the diagram, \(\angle BAC = \angle ADB = 90{}^\circ\). Prove that</p>
<ol class="i-list"><li><div class="list-item-paragraph">\(\angle ABD = \angle CAD\),</div></li><li><div class="list-item-paragraph">\(\Delta ABD\) is similar to \(\Delta CAD\),</div></li><li><div class="list-item-paragraph">\(AD^2 = BD \times CD\).</div></li></ol>
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In the diagram, \(\angle BAC = \angle ADB = 90{}^\circ\). Prove that

\(\Delta ABD\) is similar to \(\Delta CAD\)

\(\Delta ABD\) is similar to \(\Delta CAD\),

Proofs in Plane Geometry

Question 0911746e

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