Differentiate \\(x \\cos 3x\\) with respect to \\(x\\). Hence, show that \\(\\displaystyle\\int_{0}^{\\frac{\\pi}{9}} x \\sin 3x \\, \\mathrm{d}x = \\frac{\\sqrt{3}}{18} - \\fr

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Definite Integrals and Area under graph - Definite Integration as the Reverse of Differentiation

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