Equation whose roots are the ratios of two roots

Equation whose roots are the ratios of two roots

IP 3
7 marks

The equation \(x^2-sx+1=0\), where \(s\) is a constant and \(s^2>4\), has roots \(\alpha\) and \(\beta\).

  1. Show that the equation whose roots are \(\dfrac{\alpha}{\beta}\) and \(\dfrac{\beta}{\alpha}\) is \(x^2-(s^2-2)x+1=0\).[3]
  2. Write down this equation when \(s=3\).[1]
  3. Find the possible values of \(s\) for which one root of \(x^2-sx+1=0\) is four times the other.[3]

Solution:

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Answer:(a) shown (b) \(x^2-7x+1=0\) (c) \(s=\pm\dfrac{5}{2}\)

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