Fractional equations with two denominators and a rejected root
Fractional equations with two denominators and a rejected root
Secondary 3
Solve each equation. State the values of \(x\) that are not allowed, and explain any root you reject.
- \(\dfrac{2}{x+2}+\dfrac{x}{x-2}=\dfrac{8}{x^2-4}\)
- \(\dfrac{x}{x-3}-\dfrac{1}{x+1}=\dfrac{4}{(x-3)(x+1)}\)
Solution:
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Answer:(a) \(x\ne2,-2\); \(x=-6\) (reject \(x=2\)) (b) \(x\ne3,-1\); \(x=1\) (reject \(x=-1\))
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