Parabola-line graph interpretation

Parabola-line graph interpretation

Secondary 2
10 marks
TGM Original Questions

Optional extension

The graphs \(y=x^2-4x-5\) and \(y=2x-5\) are shown.

  1. Find their intersection points.[2]
  2. From the graph estimate solutions of
    1. \(x^2-4x-5=0\), and[2]
    2. \(x^2-4x=4\).[2]
  3. State the parabola’s symmetry line.[2]
  4. Explain for which \(k\) the equation \(x^2-4x-5=k\) has no real solution.[2]

For graph readings, give values to the nearest 0.1 unit where an exact value cannot be read from the grid. Use the labelled axes and grid provided.

Solution:

Solution locked

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Answer:(a) \((0,-5),(6,7)\) (b)(i) \(x=-1,5\) (ii) \(x\approx-0.8,4.8\) (c) \(x=2\) (d) \(k<-9\).

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