Consider the function \(y=x^2-2x-3.\)
Complete the table.
| \(x\) | \(-2\) | \(-1\) | \(0\) | \(1\) | \(2\) | \(3\) | \(4\) |
|---|---|---|---|---|---|---|---|
| \(y\) |
Draw the curve for \(-2\le x\le4\). Use a vertical range of \(-5\le y\le6\).
On the same axes, draw the horizontal line \(y=2\).
Use the intersections to solve\[ x^2-2x-5=0. \]
Give your answers to 1 decimal place and explain why the line \(y=2\) is appropriate.
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