Solve $ \frac{3}{x-1}+\frac{2}{x+1}=2. $ $\frac{1}{x-2}+\frac{2}{x}=1. $ \(\frac{2}{x+1}+\frac{1

Question

Solve $ \frac{3}{x-1}+\frac{2}{x+1}=2. $ $\frac{1}{x-2}+\frac{2}{x}=1. $ $\frac{2}{x+1}+\frac{1}{x-1}=1. $

Accepted Answer

(a) $x\ne1,-1$; $x=3$ or $-\frac12$ (b) $x\ne2,0$; $x=1$ or $4$ (c) $x\ne-1,1$; $x=0$ or $3$

Quadratic Functions, Equations and Inequalities