The roots of $x^2-6x+4=0$ are $\alpha,\beta$. Find: $\alpha^2+\beta^2$ $\alpha^3+\beta^3$ \(

Question

The roots of $x^2-6x+4=0$ are $\alpha,\beta$. Find: $\alpha^2+\beta^2$ $\alpha^3+\beta^3$ $\dfrac1\alpha+\dfrac1\beta$.

Accepted Answer

(a) $28$; (b) $144$; (c) $\frac32$

Quadratic Functions, Equations and Inequalities