Solve each equation. Identify any rejected root and explain why it is unacceptable. \( \frac{x^2-9}{

Question

Solve each equation. Identify any rejected root and explain why it is unacceptable. $ \frac{x^2-9}{x-3}=6. $ $ \frac{x^2-4}{x-2}=3x. $ $ \frac{x^2-16}{x+4}=2x+1. $

Accepted Answer

(a) $x\ne3$; No solutions; reject $x=3$ (b) $x\ne2$; $x=1$; reject $x=2$ (c) $x\ne-4$; $x=-5$; reject $x=-4$

Quadratic Functions, Equations and Inequalities

Quadratic Functions, Equations and Inequalities