Solving a quadratic in a geometric setting

Solving a quadratic in a geometric setting

Secondary 2
4 marks
TGM Original Questions

In the diagram, \(ABCD\) is a square of side 25 cm. Points \(P,Q,R,S\) lie on \(AB,BC,CD,DA\), respectively, and \(BP=CQ=DR=AS=x\)cm. It is given that the dimensions satisfy \(x^2-25x+144=0\).

  1. Factorise \(x^2-25x+144\).[1]
  2. Solve the given equation.[2]
  3. Given \(DR<RC\), find \(DR\).[1]

Solution:

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Answer:(a) \((x-9)(x-16)\). (b) \(x=9\)or 16. (c) \(DR=9\)cm.

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