Consider the function \(y=-x^2+4x+1.\)
Complete the table and draw the curve for \(-1\le x\le5\). Use a vertical range of \(-5\le y\le6\).
| \(x\) | \(-1\) | \(0\) | \(1\) | \(2\) | \( 3\) | \(4\) | \(5\) |
|---|---|---|---|---|---|---|---|
| \(y\) |
On the same axes, draw the straight line \(y=x+2. \)
State two points used to draw the line. Read the \(x\)-coordinates of its intersections with the curve to \(1\) decimal place.
Show that your graphical answers solve \( x^2-3x+1=0. \)
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