<p><strong>Answer the whole of this question on a sheet of graph paper.</strong></p>
<p>The variables $x$ and $y$ are connected by the equation $y=\frac{1}{2}(2-x)(5+x)$.</p>
<p>The table below shows some values of $x$ and the corresponding values of $y$.</p>
<div class="content-block content-block--table"><div class="table-container"><table style="table-layout: fixed; width: 500px;"><colgroup><col style="width: 50px;"><col style="width: 50px;"><col style="width: 50px;"><col style="width: 50px;"><col style="width: 50px;"><col style="width: 50px;"><col style="width: 50px;"><col style="width: 50px;"><col style="width: 50px;"><col style="width: 50px;"></colgroup><thead><tr style="height: 23px;"><th style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p><em>$x$</em></p></th><th style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$-5$</p></th><th style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$-4$</p></th><th style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$-3$</p></th><th style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$-2$</p></th><th style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$-1$</p></th><th style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$0$</p></th><th style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$1$</p></th><th style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$2$</p></th><th style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$3$</p></th></tr></thead><tbody><tr style="height: 23px;"><td style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p><em>$y$</em></p></td><td style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$0$</p></td><td style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$3$</p></td><td style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p><em>$p$</em></p></td><td style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$6$</p></td><td style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$6$</p></td><td style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$5$</p></td><td style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$3$</p></td><td style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$0$</p></td><td style="height: 23px; min-height: 23px; text-align: center; --cell-justify: center"><p>$-4$</p></td></tr></tbody></table></div></div>
<ol class="abc-list"><li><div class="list-item-paragraph">Find the value of $p$.</div></li><li><div class="list-item-paragraph">Using a scale of $2$ cm to 1 unit on each axis, draw the graph of the equation$y=\frac{1}{2}(2-x)(5+x)$ for&nbsp;$-5\le x\le 3$.</div></li><li><div class="list-item-paragraph">Hence, use your graph to solve the equation $(2-x)(5+x)=8$.</div></li></ol>

**Answer the whole of this question on a sheet of graph paper.**

The variables $x$ and $y$ are connected by the equation $y=\frac{1}{2}(2-x)(5+x)$.

The table below shows some values of $x$ and the corresponding values of $y$.

Using a scale of $2$ cm to 1 unit on each axis, draw the graph of the equation$y=\frac{1}{2}(2-x)(5+x)$ for $-5\le x\le 3$.

Hence, use your graph to solve the equation $(2-x)(5+x)=8$.

Quadratic Expressions, Equations, and Functions

Quadratic Expressions, Equations, and Functions