Quadratic Equation from a Distance–Speed–Time Problem

Quadratic Equation from a Distance–Speed–Time Problem

Secondary 2

Gilbert cycled at a speed of \(\left( x+4 \right)\) km/h for \(2x\) hours. He then jogged at a speed of \(\left( x-2 \right)\) km/h for \(x\) hours. If the total distance he travelled is \(45\) km, find

  1. an expression for the distance he cycled.
  2. an expression for the distance he jogged.
  3. Hence or otherwise, form an equation in \(x\) and shows that it reduces to \({{x}^{2}}+2x-15=0\).
  4. Solve the equation \({{x}^{2}}+2x-15=0\) and state the reason why one of the values of \(x\) is rejected.
  5. Hence, or otherwise, find the average speed for Gilbert’s journey.

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Answer:(a) \(2x^2+8x\text{ km}\) (b) \(x^2-2x\text{ km}\) (c) \(x^2+2x-15=0\) (d) \(x=3\) (e) \(5\text{ km/h}\)

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