The diagram shows triangle ABC with AB=9 cm, AC=12 cm and BC=15 cm. The perpendicular distance from

Question

The diagram shows triangle ABC with AB=9 cm, AC=12 cm and BC=15 cm. The perpendicular distance from A to BC is d. Prove that $ABC$ is right-angled. Find $d$. $A$ $B$ $C$ $\text{9 cm}$ $\text{12 cm}$ $\text{15 cm}$ $d$

Accepted Answer

(a) $9^2+12^2=15^2$, so $\angle A=90^\circ$; (b) $d=7.2$ cm.

Pythagoras and an altitude

Pythagoras and an altitude

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