In \(\Delta ABC\), \(BQ\) and \(CP\) intersect at \(O\). \(P\), \(Q\), \(R\) and \(S\) are the midpoints of \(AB\), \(AC\), \(OC\) and \(OB\) respectively. Prove that \(PQRS\) is a parallelogram. Hence, show that \(OS = \frac{1}{3} BQ\).

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