Proofs in Plane Geometry - Alternate Segment Theorem

Proofs in Plane Geometry - Alternate Segment Theorem

In the diagram, \(PT\) is a tangent to the semicircle \(APB\). If \(PB\) bisects \(\angle ABT\), prove that \(\angle BTP=90{}^\circ \).

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Answer:Proved: \(\angle BTP=90^\circ\)

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