<p>In the diagram, \(ABCD\) is a cyclic quadrilateral with \(BC = CD\) and \(BC\) is parallel to \(AD\). The tangent to the circle at \(B\) intersects \(DA\) produced at \(T\). Prove that</p>
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<ol class="i-list"><li data-list-item-id="item-i" data-list-item-path="item-i"><div class="list-item-paragraph">angle \(ABT = \text{angle}\hspace{0.5em} BDC\), and</div></li><li data-list-item-id="item-ii" data-list-item-path="item-ii"><div class="list-item-paragraph">triangle \(BAT\) is an isosceles triangle.</div></li></ol>

In the diagram, \(ABCD\) is a cyclic quadrilateral with \(BC = CD\) and \(BC\) is parallel to \(AD\). The tangent to the circle at \(B\) intersects \(DA\) produced at \(T\). Prove that

triangle \(BAT\) is an isosceles triangle.

Proofs in Plane Geometry - Alternate Segment Theorem

Proofs in Plane Geometry - Alternate Segment Theorem

Video Solution:

Solution:

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