Circle proofs draw on a fixed toolbox of theorems. Each row below gives the statement together with a standard reason phrasing; equivalent mathematically precise wording is also valid. In every diagram, \(O\) is the centre of the circle.
Symmetry and tangent properties
| Property | Statement and reason | Diagram |
|---|---|---|
| Perpendicular bisector of a chord | The perpendicular from the centre bisects the chord, and the perpendicular bisector of a chord passes through the centre. If \(OM\perp AB\), then \(AM=BM\). (\(\perp\) bisector of chord) | |
| Equal chords | Equal chords are equidistant from the centre. If \(AB=CD\), then \(OM=ON\). (equal chords, equidistant from centre) | |
| Tangent and radius | A tangent is perpendicular to the radius drawn to the point of contact. \(OA\perp PQ\) (tangent \(\perp\) radius) | |
| Tangents from an external point | Tangents from an external point are equal in length, and the line to the centre bisects the angle between them. \(PA=PB\) (tangents from an external point) |
Angle properties
| Property | Statement and reason | Diagram |
|---|---|---|
| Angle at the centre | The angle at the centre is twice any angle at the circumference standing on the same arc. \(\angle AOB=2\angle ACB\) (\(\angle\) at centre \(=2\angle\) at circumference) | |
| Angle in a semicircle | If \(AB\) is a diameter, the angle at the circumference is a right angle. \(\angle ACB=90^\circ\) (\(\angle\) in semicircle) | |
| Angles in the same segment | Angles standing on the same chord, on the same side of it, are equal. \(\angle ACB=\angle ADB\) (\(\angle\)s in the same segment) | |
| Angles in opposite segments | Opposite angles of a cyclic quadrilateral are supplementary. \(a+b=180^\circ\) (\(\angle\)s in opposite segments) | |
| Alternate segment theorem | The angle between a tangent and a chord equals the angle in the alternate segment. \(\angle PAB=\angle ACB\) (Alternate Segment Theorem) |
A right angle at the circumference needs the chord to be a diameter — check before quoting (\(\angle\) in semicircle). For the alternate segment theorem, name the tangent and the chord, then take the equal angle on the other side of the chord.
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