<p>In the diagram, \(TA\) is the tangent to the circle at \(A\). \(TDE\) and \(TCB\) are straight lines such that&nbsp;\(AD = AE\). Prove that</p>
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<ol class="i-list"><li data-list-item-id="item-i" data-list-item-path="item-i"><div class="list-item-paragraph">angle \(TDC = \) angle \(TEA\) , and</div></li><li data-list-item-id="item-ii" data-list-item-path="item-ii"><div class="list-item-paragraph">\(TDE\) bisects angle \(ATB\) .</div></li></ol>

In the diagram, \(TA\) is the tangent to the circle at \(A\). \(TDE\) and \(TCB\) are straight lines such that \(AD = AE\). Prove that

Proofs in Plane Geometry - Alternate Segment Theorem

Proofs in Plane Geometry - Alternate Segment Theorem

Video Solution:

Solution:

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