In the figure, two circles touch at $C$ and $CD$ is a common tangent. $AD$ and $BD$ are tang

Question

In the figure, two circles touch at $C$ and $CD$ is a common tangent. $AD$ and $BD$ are tangents to the larger and smaller circles respectively. Show that $AD=BD$.

Accepted Answer

AD = BD (proved).

Properties of Circle - Equal Tangents from an External Point

Properties of Circle - Equal Tangents from an External Point

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