Proofs in Plane Geometry - Similarity

Proofs in Plane Geometry - Similarity

In the diagram, \(ABCD\) is a rectangle and \(PC\) is perpendicular to \(BD\). Prove that

\(\Delta ABD\) is similar to \(\Delta PDC\),
\(AB^2 = BD \times PD\).

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Answer:(i) Proved: \(\triangle ABD\sim\triangle PDC\) (ii) Proved: \(AB^2=BD\times PD\)

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