In the figure, the smaller circle $ABDE$ intersects the larger circle $BCD$ at $B$ and $D$.

Question

In the figure, the smaller circle $ABDE$ intersects the larger circle $BCD$ at $B$ and $D$. Given that $ABC$ and $EDC$ are straight lines and that $BE$ is the diameter of the smaller circle $ABDE$, prove that $BC$ is the diameter of the larger circle.

Accepted Answer

Proved: $BC$ is the diameter of the larger circle

Properties of Circle - Angles in a Semicircle and the Converse

Properties of Circle - Angles in a Semicircle and the Converse

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