Proofs in Plane Geometry - Alternate Segment Theorem

Proofs in Plane Geometry - Alternate Segment Theorem

In the diagram, \(AC\) is a diameter of the circle with centre \(O\). \(ACD\) is a straight line and \(AB=BD\). Prove that

  1. \(BC=DC\),
  2. \(\angle BAC=30{}^\circ \).

\(BD\) is tangent to the circle at \(B\).

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Answer:(a) Proved: \(BC=DC\) (b) \(\angle BAC=30^\circ\)

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