<p>In triangle \(ABC\), \(M\) and \(N\) are the midpoints of \(AB\) and \(AC\), respectively. \(PMNQ\) is a straight line such that&nbsp;\(BP\), \(CQ\) are perpendicular to \(PMNQ\). Prove that</p>
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<ol class="i-list"><li data-list-item-id="item-i" data-list-item-path="item-i"><div class="list-item-paragraph">quadrilateral \(BCQP\) is a rectangle, and</div></li><li data-list-item-id="item-ii" data-list-item-path="item-ii"><div class="list-item-paragraph">area of triangle \(ABC =\) area of quadrilateral \(BCQP\).</div></li></ol>

In triangle \(ABC\), \(M\) and \(N\) are the midpoints of \(AB\) and \(AC\), respectively. \(PMNQ\) is a straight line such that \(BP\), \(CQ\) are perpendicular to \(PMNQ\). Prove that

quadrilateral \(BCQP\) is a rectangle, and

area of triangle \(ABC =\) area of quadrilateral \(BCQP\).

Proofs in Plane Geometry - Midpoint Theorem

Proofs in Plane Geometry - Midpoint Theorem

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Solution:

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