Proofs in Plane Geometry - Similarity

Proofs in Plane Geometry - Similarity

TGM Original Questions

In rectangle \(ABCD\), \(P\), \(S\) are on the side \(AD\). \(BD\) and \(BP\) divide angle \(ABC\) into \(3\) equal parts, \(CS\) bisects angle \(BCD\) and \(BD\), \(CS\) intersect at \(M\). Prove that

  1. triangles \(ABP\) and \(CBD\) are similar,
  2. \(AD = 3AP\),
  3. \(AD = \left( 6 + 3\sqrt{3} \right)PS\), and
  4. \(CM = \sqrt{3}MS\).

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs a course plan.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.

Need help? Join our A-Maths tuition classes.

Learn more