<p>In the diagram, \(TA\) is the tangent to the circle at \(A\) and is parallel to \(CB\). Given that&nbsp;\(TDC\) is a straight line, prove that</p>
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<ol class="i-list"><li data-list-item-id="item-i"><div class="list-item-content"><span class="list-item-text">angle \(ATD =\) angle \(BAD\), and</span></div></li><li data-list-item-id="item-ii"><div class="list-item-content"><span class="list-item-text">\(BA \times TD = AT \times AD\).</span></div></li></ol>

In the diagram, \(TA\) is the tangent to the circle at \(A\) and is parallel to \(CB\). Given that \(TDC\) is a straight line, prove that

Proofs in Plane Geometry

Proofs in Plane Geometry

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