In the diagram, $TA$ is the tangent to the circle at $A$ and is parallel to $CB$. Given that&n

Question

In the diagram, $TA$ is the tangent to the circle at $A$ and is parallel to $CB$. Given that $TDC$ is a straight line, prove that angle $ATD =$ angle $BAD$, and $BA \times TD = AT \times AD$.

Accepted Answer

(i) $\angle ATD=\angle BAD$; (ii) $BA\times TD=AT\times AD$.

Proofs in Plane Geometry - Alternate Segment Theorem

Proofs in Plane Geometry - Alternate Segment Theorem

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