Scale factor lab

<p>In the diagram, \(PT\) is the tangent to the semicircle with centre \(O\) at \(P\) and \(BP\) bisects angle \(ABT\). Prove that</p>
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<ol class="i-list"><li data-list-item-id="item-i" data-list-item-path="item-i"><div class="list-item-paragraph">triangles \(BTP\) and \(BPA\) are similar, and</div></li><li data-list-item-id="item-ii" data-list-item-path="item-ii"><div class="list-item-paragraph">angle \(BTP = 90^{\circ}\).</div></li></ol>

In the diagram, \(PT\) is the tangent to the semicircle with centre \(O\) at \(P\) and \(BP\) bisects angle \(ABT\). Prove that

Proofs in Plane Geometry - Alternate Segment Theorem

Proofs in Plane Geometry - Alternate Segment Theorem

Video Solution:

Solution:

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