In the figure, $TA$ is a tangent to the circle at $A$ and is parallel to $CB$. Given that&nbsp

Question

In the figure, $TA$ is a tangent to the circle at $A$ and is parallel to $CB$. Given that $TDC$ is a straight line, prove that $\angle ATD = \angle BAD$, $BA \times TD = AT \times AD$.

Accepted Answer

(i) Proved: $\angle ATD=\angle BAD$ (ii) Proved: $BA\times TD=AT\times AD$

Proofs in Plane Geometry - Alternate Segment Theorem

Proofs in Plane Geometry - Alternate Segment Theorem

Video Solution:

Solution:

Solution locked