In the diagram, $BFD$, $AFC$ and $BEC$ are straight lines. It is given that $AF = FC$,

Question

In the diagram, $BFD$, $AFC$ and $BEC$ are straight lines. It is given that $AF = FC$, $BF = FD$ and $BE = EC$. Prove that $FE = \frac{1}{2} AB$, and $AB = DC$.

Accepted Answer

(i) $FE=\frac12AB$; (ii) $AB=DC$.

Proofs in Plane Geometry - Midpoint Theorem

Proofs in Plane Geometry - Midpoint Theorem

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