In the diagram, $P$ and $Q$ are points on the sides $AC$ and $AB$ of $\Delta ABC$ respecti

Question

In the diagram, $P$ and $Q$ are points on the sides $AC$ and $AB$ of $\Delta ABC$ respectively, and $\angle APQ = \angle ABC$. Prove that $\Delta APQ$ is similar to $\Delta ABC$, $AP \times AC = AQ \times AB$.

Accepted Answer

(i) Proved: $\triangle APQ\sim\triangle ABC$ (ii) Proved: $AP\times AC=AQ\times AB$

Proofs in Plane Geometry - Similarity

Proofs in Plane Geometry - Similarity

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