Proofs in Plane Geometry - Angles at the Centre and Circumference
Proofs in Plane Geometry - Angles at the Centre and Circumference
In the figure, \(O\) is the centre of the circle \(ABCD\). The smaller circle \(AOKD\) intersects the larger circle at \(A\) and \(D\). Given that \(AOB\), \(AKC\) and \(BKD\) are straight lines, prove that
- \(DK = CK\),
- \(BKD\) bisects \(\angle ODC\).
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Answer:(i) Proved: \(DK=CK\) (ii) Proved: \(BKD\) bisects \(\angle ODC\)
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